3(×+4)= ײ -16
merci d'avance
bonsoir
3 x + 12 = x² - 16
( 3 x + 12 ) - ( x ² - 16 ) = 0
3 ( x + 4 ) - ( x - 4 ) ( x + 4 ) = 0
( x + 4 ) [3 - ( x - 4 ) = 0
( x + 4 ) ( 3 - x + 4 ) = 0
( x + 4 ) ( - x + 7 ) = 0
x = - 4 ou 7
3(×+4)= ײ -16
merci d'avance
bonsoir
3 x + 12 = x² - 16
( 3 x + 12 ) - ( x ² - 16 ) = 0
3 ( x + 4 ) - ( x - 4 ) ( x + 4 ) = 0
( x + 4 ) [3 - ( x - 4 ) = 0
( x + 4 ) ( 3 - x + 4 ) = 0
( x + 4 ) ( - x + 7 ) = 0
x = - 4 ou 7
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